Get itemtype for a flowitem in a task

Hi all,

I want to set a condition in dispatcher whether the task would dispatch to a port for a specific itemtype, but I don know how to set the condition using getitemtype(object) <----what's the object of a task?? (actually i'm new in setting the task sequence), can anyone give me a hand, thanks.

Regards,
Kelvin

Hello Kelvin,

On the PassTo requirement of the dispatcher you could write:

treenode item = gettaskinvolved( gettasksequence( current, 1 ), 2, 1 );
int tasktype = getitemtype( item );

return tasktype;

I have attached a model with a queue that collects boxes (type1) and loaded pallets (type2). The dispathcer is connected to a person and a transporter. The person carries the boxes and the transporter transports the loaded pallets. Hope this helps you solve your problem.

Also take a look at the"Querying Information on Task Sequences" part of the help file.

Esther

Hi Esther,

It seems I know how your demo model works but when I apply to my model it doesn work.

in the dispatcher "Pass To" i type:

if ( getitemtype( gettaskinvolved( gettasksequence(current,1),2,1)) == 2)
{
return 1;
}
else
{
.....other dispatch method
}

but it seems even the item is hving itemtype 2, now still using other dispatch method
(i.e. not outport 1 operator deals with the task)

so, is it my problem in:
1. My dispatcher task source is not from 1 object only (in the demo only Queue 3)
2. The flowitem handled is a pallet(container) with itemtype2 and boxes with itemtype1 is in the pallet?
3.The task to be dispatched is a utilize task not load/unload task


Regards,
Kelvin

After reading help is it the problem is in "3.The task to be dispatched is a utilize task not load/unload task"

For a utilize task sequence the task list is travel -> utilize

If I refer to the 2nd task of the tasksequence I cant get the flowitem's itemtype, rite??

Regards,
Kelvin

Seems that problem solved by changing the if statement with:

if ( getitemtype( rank(gettaskinvolved( gettasksequence(current,1),2,1),1) == 2)