conveyor with acceleration

I have created a conveyor with accleration. However, i faced a number of problem.

1. It does not apply to all items.
2. The flowitem that acclerated was hold back for while before it is released.

Anyone has any suggestion?


David

Hi, about question one,

changed the code to this:

if (content(current)>0)
for(int xx = 1; xx <= content(current); xx++)
{
updatekinematics(label(rank(current,xx),"kin_data" ),rank(current,xx));
}

on the custom draw code and it works for all flowitems...

not sure, about question 2, i think it has to do with the conveyor speed and lenght ( the staytime of the flowitems is always the same (lenght/speed) = 20sec) .. if you set speed of the conveyor to about 7.8, it looks like items will exit at convey end, this you have to calculate with the lenght of the conveyor, initial speed and acceleration of the kinematic..

regards

Pablo Concha E.

I may have missed the point here, since I'm not sure exactly what you're trying to do, but attached is a simple example of the basic conveyor using acceleration for anyone who is interested.

The bcsetitemconveystate is called on entry.
A decision point at 1metre is used to receive the next item
Another decision point at the end is used to release the item.

The basic conveyor handles everything else, including the drawing of flowitems and the updating of the flowitem's basic conveyor kinematic data. So no OnDraw code with updatekinematics is necessary.

The idea of adding further kinematics to the flowitem is so that you can make it elevate or rotate in addition to the standard translation along the basic conveyor (as defined by bcsetitemconveystate).

That is very very cool. I did not know there is such new command for basic conveyor. Thanks Jason!!

David

Originally Posted by Jason Lightfoot

I may have missed the point here, since I'm not sure exactly what you're trying to do, but attached is a simple example of the basic conveyor using acceleration for anyone who is interested.

The bcsetitemconveystate is called on entry.
A decision point at 1metre is used to receive the next item
Another decision point at the end is used to release the item.

The basic conveyor handles everything else, including the drawing of flowitems and the updating of the flowitem's basic conveyor kinematic data. So no OnDraw code with updatekinematics is necessary.

The idea of adding further kinematics to the flowitem is so that you can make it elevate or rotate in addition to the standard translation along the basic conveyor (as defined by bcsetitemconveystate).

Hi, Jason. Could you tell me how to let item stand up? I tried, but failed.

Attached is the same example with an additional kinematic to rotate the item into the upright position. The type 2 kinematic node of the item is used when distance on the conveyor should be used to progress the kinematic, and is found using the bcgetitemkinematics function. If you want to base the kinematic on time, you should use type1.

I've used type 2 in the example which is found in the EntryTrigger of the BasicConveyor (green) in the model. I've rotated the item through -90 in the Y-axis, at a speed of 90 degrees per metre (or 'distance unit'). I start the kinematic at 1.5 metres down the conveyor.

The code looks like this:

 
treenode kin2 = bcgetitemkinematics(current, item, 2);
initkinematics(kin2, 0,0,0, 0,0,0, 0,0);
addkinematic(kin2, 0,-90,0,90,0,0,0,0, 1.5, KINEMATIC_ROTATE

If you are using type 1, anything that uses a distance as a reference (startpoint, speed, acceleration) would instead reference time.

NOTE: You should not add or alter kinematics on the node returned for type 0 which holds main convey state kinematics.

This version rotates through the x-axis for different hight objects and lowers them onto the conveyor at the same time.

Thanks. I see the model, and I set the rotate to 90( this is what I want).
This time, the item will bury half of itself in the conveyor.

I set the centroid of items(Textured Colored Box) to 0 in the tree, still not good. Any idea?

If you set the z offest of the conveyor to +0.1 then the boxes look ok when they are rotated but are flaoting above the conveyor beforehand.

I guess what you need to to is alter the z position of the boxes when you rotate them in order to maintain contact with the conveyor.

Anth