Call subtask problem.

Hi, in the attached model, I use queue1 and queue2 to do CALL SUBTASK.

But I find that if the interarrival time of FlowitemTE is too short, only one will pickup item in queue2, how to resolve it?

Hi Qin tian,

Although I do not understand why you do not use regular taskexecuters, here's some help:

The problem is that the travel task at Queue1 is executed instantanuously, because you do not use a network at this point. So, at the time the second operator arrives it makes a reference to the same flowitem to pick it up.

I've added a possible solution in which I've changed the travel task for a pick offset task to make sure the travel offset is executed.

If you already know which item you're going to pick up, you could also at a label on the flowitems "Reserved". When you arrive at Queue1 you search for the first available item where the "Reserved" label is still zero and immediately set it to one. This is a saver option, if you would use regular task executer. I've also added this model to give you an idea.

Martijn

Hi, Martijn, thank you.
The solution of using label is good.
The solution of using pick offset task has some problem. If operators arrive at same time, they will get same item.

Definitely true,

With the pickoffset task you do not completely solve the problem, but you minimize the change it happes. After the pick-offset you still load the first( Queue2 ). When the operators arrive at the same time, they both want to pick up the same item.

Making reservations is always better. Still, when there are no more flowitems to reserve, the operators do not know what to do when they arrive at the first queue, so there's a possible challenge for you there.

Good luck anyway,
Martijn