Is there any method to add section to conveyor using flexscript command?

Hi, everyone.If i wanna add new sections to a conveyor,such as a straight one or a curved on,what kind of command can i use?
I try to use the setnodenum.but the section name is blank which you can see in the next pic.So i can't get the node path.
Generally,I wanna add new sections to conveyor using command instead of operating the layout tab in properties.Anyone can give me suggestion,thank you in advance.

Just create the following user commands:

addStraightSection (obj conveyor, num length [,num legs, num rise])

treenode conv=parnode(1);
treenode sections=getvarnode(conv,"sections");
int numsections=content(sections)+1;
settablesize(sections,numsections,CONVSEC_STARTANGLE);
settablenum(sections,numsections,CONVSEC_TYPE,CONVSECTYPE_STRAIGHT);
settablenum(sections,numsections,CONVSEC_LENGTH,parval(2));
settablenum(sections,numsections,CONVSEC_NROFLEGS,parval(3));
settablenum(sections,numsections,CONVSEC_RISE,parval(4));
setnodename(rank(sections,numsections),concat("section ",numtostring(numsections,0,0)));

addCurvedSection (obj conveyor, num angle, num radius [,num legs, num rise])

treenode conv=parnode(1);
treenode sections=getvarnode(conv,"sections");
int numsections=content(sections)+1;
settablesize(sections,numsections,CONVSEC_STARTANGLE);
settablenum(sections,numsections,CONVSEC_TYPE,CONVSECTYPE_CURVED);
settablenum(sections,numsections,CONVSEC_ANGLE,parval(2));
settablenum(sections,numsections,CONVSEC_RADIUS,parval(3));
settablenum(sections,numsections,CONVSEC_NROFLEGS,parval(4));
settablenum(sections,numsections,CONVSEC_RISE,parval(5));
setnodename(rank(sections,numsections),concat("section ",numtostring(numsections,0,0)));

Well done,Jason.Thanks.It's a good idea for me.

And now,If i wanna change the the section's type(from type 1 to type 2) of the conveyor using flexscript instead of user command ,supposing there is only one section in the conveyor,how can i get the node path.Or should i set the section's name(you know it is blank in the tree) before i change it's type?

Is my question clear?Thank all of you.

To rename based on the section rank replace <index> with the number you want - 1 in the case of one section.

setnodename(rank(sections,<index>), "newsectionname");

so similarly it's:

settablenum(sections,<index>,CONVSEC_TYPE,CONVSECTYPE_STRAIGHT);

or

settablenum(sections,<index>,CONVSEC_TYPE,CONVSECTYPE_CURVED);

to change a given section's type.

And if you know the section name is unique (e.g. Section5 ) you can find the index with:

int sectionindex=getrank(node("/Section5",sections));

Hi,Jason, acturally i am not so clearly what's your method in the second post.Here is my goal.
For example,i have a conveyor named "Conveyor2" in my mode which has one straight section.Now I want to change it into curved.If the section's name is "section1",then i will use the command in script as follows:

setnodenum(node("/Conveyor2>variables/sections/section1/type",model()),2);

.It will change the section's type into curved.But the section's name isn't anything.It is blank.Then how can I get the node path?Or is there any other mothed to achieve my goal? I don't know how to use the index.I also can't use the user command method.
BTW,is this a bug in 4.52 ? Because i know the section's name is exist in flexsim 3.0.The first section's name will be "section1" in 3.0 vision.

You can reference to a node by name or by rank in the same statement.
Let’s say you want to reference to a node by name (section1)
setnodenum(node("/Conveyor2>variables/sections/section1/type",model()),2);

Now reference to the same node by rank (1)
setnodenum(node("/Conveyor2>variables/sections/1/type",model()),2);

There is a command called nodetopath(). Make a node so() and then write into the script:
nodetopath(so()); which returns the reference to the node by ranks.
Nodetopath(so(),1); which returns the reference to the node by names.


By the way, reference to a node by rank is faster than by name, but it might be less understandable ...

I hope this makes everything a bit more clear. If not, feel free to ask again.

Thanks Tom.Yeah,it makes me clear.Acturally, I have used the "rank(1)",but I thought it doesn't work because it shows "no node".Now I found it has changed the nodenum in the tree following your advice.
And thank Jason.Your advice is what I want in the next step.