Kelvin,
To your first post about the replacename() command. I would not use it in your case.
But let’s say you have a Queue in your model and you like to rename the items in the queue you could use the command as follows:
replacename(node("/Queue",model()),"ABC","DEF");
ABC 1 will transform into DEF 1.
I would use the setname() command and read the item name and modifiy it in the way I like to have it. In your case you want transform ABC 1, ABC 100 into DEF 001, DEF 100.
Here is the code I would use and again the items are in an object called Queue
// POINTER TO QUEUE
treenode Queue = node("/Queue",model());
// FOR ALL ITEMS IN QUEUE
for(int iRank = 1; iRank <= content(Queue); iRank++)
{
// GET THE CURRENT NUMBER STRING
string sNumber = stringcopy(getname(rank(Queue,iRank)),5,3);
// TRANSFORM NUMBER STRING INTO INTEGER
int iNumber = stringtonum(sNumber);
// CHECK NUMBER AND SET STARTING ZEROS
if(iNumber < 10) sNumber = concat("00",sNumber);
if(iNumber >= 10 && iNumber < 100) sNumber = concat("0",sNumber);
// SET NEW NAME OF ITEM
setname(rank(Queue,iRank),concat("DEF ",sNumber));
}
If you want to keep the existing name you could also use stringcopy() to store the name depending on its length.
Depending on the length of your name and the number of starting zeros you like to have you need to modify the code a bit. But I am pretty sure, that you can figure this out by yourself.
There are a lot of more string commands which can be used like stringcopy(), stringreplace(), stringsearch(), etc.
So I am not sure if there is not a more elegant way to solve it (with less code), but that’s the way I would go. But maybe someone else has a nicer solution?
__________________
tom the (A)tom: "We have solved our problems ... now we have to fight the solutions."
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