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  #1  
Old 03-19-2008
rrkpradeep rrkpradeep is offline
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Default Splitting Problem

hi,

i am a engg. graduate .i am new to flexsim.i am doin a project on process simulation.i have a problem.in the file I have attached i have a separator16. It has to duplicate the item which flows in from processor3 and it has to sent the two duplicated items into processor5 and processor6 each at a time.can any one help me out .


Regards
Pradeep
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File Type: zip process.zip (51.4 KB, 299 views)
  #2  
Old 03-19-2008
Pablo Concha Pablo Concha is offline
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Hello,

i took a look at the model and my opinion, becouse the processors after the separator have a maximum content of 1, and you are not using a queue in betwen separator and processors; if you use the default send to port on the flow tab on the processor (that is first available port) it should work as you want it to, ... round robin works too...

regards,

Pablo Concha E.
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  #3  
Old 03-19-2008
Kris Geisberger Kris Geisberger is offline
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Yes, you have an error in the Separator16 Send To Port evaluation. As Pablo said, change the Separator16 Send To Port to either "First available" (the default option) or "Round Robin".

Kris
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  #4  
Old 03-19-2008
rrkpradeep rrkpradeep is offline
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Default splitting problem

hi,

Thanks for the reply.i have rectified the send to port error.can u tell me why there is a slight delay for both the items from processor10 and processor11 to meet in the combiner.Coz the process timings for processors 10 and 11 is same.


Thanks & Regards
pradeep
  #5  
Old 03-19-2008
Kris Geisberger Kris Geisberger is offline
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Pradeep,

You have entered normal(50,15) (a statistical distribution) into the Process Time of both Processor10 and 11. Although in writing they are identical, each time it is executed it will randomly return a value within the statistical curve. So, Processor10 and 11 have the same behavior, but they are not likely to exhibit the same processing time at a given moment in time.

I question whether normal(50,15) is a true representation of the process time because with such a large standard deviation (15) relative to the mean (50) this distribution will surely return a negative process time at some point.

Kris
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  #6  
Old 03-19-2008
rrkpradeep rrkpradeep is offline
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Default splitting problem

hi kris,

Thank u for the reply.ill try to verify the data from the sources.


Thanks & Regards,
Pradeep



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